Elementry Algebra deals with symbols, usually letters of the alphabet, represent numbers or members of a specified set and are used to represent quantities and to express general relationships that hold for all members of the set. Algebra can include complex numbers, real numbers, matrices, vectors etc. Moving from Arithmetic to Algebra will look something different like this: Arithmetic: 3 + 5 = 5 + 3 in Algebra it would look like: a + b = b +a.
elementary algebra solutions- Example problems:
Elementry algebra Example Problem 1:
Evaluate 2x2 - y2 - z if x = 3, y = -1 and z = -2
Solution:
Substitute the values for the variables;
= 2(3)2 - (-1)2 - (-2)
= 2(9) - (1) - (-2)
= 18 - (1) + (+2)
= 17 + 2
= 19
Elementry Algebra Example Problem 2:
Solve for x: 1 - 3(x - 4) = 2(3x + 1) 7
Solution:
Distribute:
1 - 3x +12 = 6x + 2 - 7
Collect like terms:
-3x +13 = 6x - 5
Add 3x to both sides of the equal sign:
-3x +13 + 3x = 6x - 5 + 3x
13 = 9x - 5
Add 5 to both sides:
18 = 9x
Divide both sides by 9:
2 = x
Elementry Algebra Example Problem 3:
Solve for y: ax + by =c
Solution:
Subtract ax from both sides:
by = c - ax
Divide both sides by b:
y= '(c-ax)/(b)'
Elementry Algebra Example Problem 4:
Solve the equation
5(-3x - 2) - (x - 3) = -4(4x + 5) + 13
Solution:
Given the equation
5(-3x - 2) - (x - 3) = -4(4x + 5) + 13
Multiply factors.
-15x - 10 - x + 3 = -16x - 20 +13
Group like terms.
-16x - 7 = -16x - 7
Add 16x + 7 to both sides and then write the equation as follows
0 = 0
The above equation is true for all values of x and therefore all real numbers are solutions to the given equation.
Elementry Algebra Example Problem 5:
Simplify the expression
2(a -3) + 4b - 2(a -b -3) + 5
Solution:
Given the algebraic expression
2(a -3) + 4b - 2(a -b -3) + 5
Multiply factors.
= 2a - 6 + 4b -2a + 2b + 6 + 5
Group like terms.
= 6b + 5
This will help you learn elementary algebra solutions .
Check this cbse class ix sample papers awesome i recently used to see.
Elementary algebra is the basic and relatively necessary form of algebra. Elementary Algebra should be distinguished from theoretical algebra, which is a additional advanced field of study.
The some elementary algebra for college student problem for given below:
Problems in Elementary Algebra for College Student :
To solve: 2x - y - z if x = 3, y = -1 and z = -2
Sol:
Plug the values for the variables; follow order of function to evaluate:
2(3) - (-1) - (-2)
= 2(9) - (1) - (-2)
= 18 - (1) + (2)
= 17 + 2
= 19
The final answer is 19.
elementary algebra for college students : Problem 2:
To find the factors of Quadratic expression: x2+8x+12 = 0
Sol:
By using complete the square method, add and subtract 4 to compensate the equation
x2 + 8x +12 +4 - 4= 0
x2 + 8x +16 -4 = 0
(x + 4)2 4 = 0
(x + 4)2 = 4
Taking square root on both sides
x + 4 = 2
x + 4 = 2, or x + 4 = -2
x = -2 or x = -6
The final answer is x =- 2 (or) x = -6
elementary algebra for college students Problem 3:
Solve Log 5 1/5
Sol:
Log 5 1/5 = log5 5-1
= - 1. Log5 5
= - 1. 1
= - 1
The final answer is 1
Prob 4:
To solve: -2 + 5 - 3(1 - 2)
Sol:
-2 + 5 - 3(1 - 2)
= -2 + 5 - 3(-1)
= -2 + 5 - 3(1)
= -2 + 5 - 3
= 3 - 3
= 0
The final answer is zero
Prob 5:
Use FOIL to multiply:
(2a - 3b)(a + 2b)
= 2a2 + 4ab - 3ab - 6b2
= 2a2 + ab - 6b2
Problem 6:
Solve for x: 1 - 3(x - 4) = 2(3x + 1) - 7
Sol:
Distribute:
1 - 3x +12 = 6x + 2 - 7
Collect like terms:
-3x +13 = 6x - 5
Add 3x to both sides of the equal sign:
-3x +13 + 3x = 6x - 5 + 3x
13 = 9x - 5
Add 5 to both sides:
18 = 9x
Divide both sides by 9:
2 = x
The answer x is 2.
elementary algebra solutions- Example problems:
Elementry algebra Example Problem 1:
Evaluate 2x2 - y2 - z if x = 3, y = -1 and z = -2
Solution:
Substitute the values for the variables;
= 2(3)2 - (-1)2 - (-2)
= 2(9) - (1) - (-2)
= 18 - (1) + (+2)
= 17 + 2
= 19
Elementry Algebra Example Problem 2:
Solve for x: 1 - 3(x - 4) = 2(3x + 1) 7
Solution:
Distribute:
1 - 3x +12 = 6x + 2 - 7
Collect like terms:
-3x +13 = 6x - 5
Add 3x to both sides of the equal sign:
-3x +13 + 3x = 6x - 5 + 3x
13 = 9x - 5
Add 5 to both sides:
18 = 9x
Divide both sides by 9:
2 = x
Elementry Algebra Example Problem 3:
Solve for y: ax + by =c
Solution:
Subtract ax from both sides:
by = c - ax
Divide both sides by b:
y= '(c-ax)/(b)'
Elementry Algebra Example Problem 4:
Solve the equation
5(-3x - 2) - (x - 3) = -4(4x + 5) + 13
Solution:
Given the equation
5(-3x - 2) - (x - 3) = -4(4x + 5) + 13
Multiply factors.
-15x - 10 - x + 3 = -16x - 20 +13
Group like terms.
-16x - 7 = -16x - 7
Add 16x + 7 to both sides and then write the equation as follows
0 = 0
The above equation is true for all values of x and therefore all real numbers are solutions to the given equation.
Elementry Algebra Example Problem 5:
Simplify the expression
2(a -3) + 4b - 2(a -b -3) + 5
Solution:
Given the algebraic expression
2(a -3) + 4b - 2(a -b -3) + 5
Multiply factors.
= 2a - 6 + 4b -2a + 2b + 6 + 5
Group like terms.
= 6b + 5
This will help you learn elementary algebra solutions .
Check this cbse class ix sample papers awesome i recently used to see.
Elementary algebra is the basic and relatively necessary form of algebra. Elementary Algebra should be distinguished from theoretical algebra, which is a additional advanced field of study.
The some elementary algebra for college student problem for given below:
Problems in Elementary Algebra for College Student :
To solve: 2x - y - z if x = 3, y = -1 and z = -2
Sol:
Plug the values for the variables; follow order of function to evaluate:
2(3) - (-1) - (-2)
= 2(9) - (1) - (-2)
= 18 - (1) + (2)
= 17 + 2
= 19
The final answer is 19.
elementary algebra for college students : Problem 2:
To find the factors of Quadratic expression: x2+8x+12 = 0
Sol:
By using complete the square method, add and subtract 4 to compensate the equation
x2 + 8x +12 +4 - 4= 0
x2 + 8x +16 -4 = 0
(x + 4)2 4 = 0
(x + 4)2 = 4
Taking square root on both sides
x + 4 = 2
x + 4 = 2, or x + 4 = -2
x = -2 or x = -6
The final answer is x =- 2 (or) x = -6
elementary algebra for college students Problem 3:
Solve Log 5 1/5
Sol:
Log 5 1/5 = log5 5-1
= - 1. Log5 5
= - 1. 1
= - 1
The final answer is 1
Prob 4:
To solve: -2 + 5 - 3(1 - 2)
Sol:
-2 + 5 - 3(1 - 2)
= -2 + 5 - 3(-1)
= -2 + 5 - 3(1)
= -2 + 5 - 3
= 3 - 3
= 0
The final answer is zero
Prob 5:
Use FOIL to multiply:
(2a - 3b)(a + 2b)
= 2a2 + 4ab - 3ab - 6b2
= 2a2 + ab - 6b2
Problem 6:
Solve for x: 1 - 3(x - 4) = 2(3x + 1) - 7
Sol:
Distribute:
1 - 3x +12 = 6x + 2 - 7
Collect like terms:
-3x +13 = 6x - 5
Add 3x to both sides of the equal sign:
-3x +13 + 3x = 6x - 5 + 3x
13 = 9x - 5
Add 5 to both sides:
18 = 9x
Divide both sides by 9:
2 = x
The answer x is 2.
SHARE